臥囉先生

$$\lfloor (20-6{)}^2+e\rfloor =198$$ $$\left(\genfrac{}{}{0ex}{}{A(2,6)}{2}\right)+0!=106$$ $$P(15,2)=15\times 14=210$$ $$\left(\genfrac{}{}{0ex}{}{A(2,6)-0!}{2}\right)=91$$ $$P(A(2,6)-0!,2)=182$$ $$\boxed{A(2,6)=15}$$